48x^2-88x-45=0

Solution for 48x^2-88x-45=0 equation:

48x^2-88x-45=0

a = 48; b = -88; c = -45;
Δ = b2-4ac
Δ = -882-4·48·(-45)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-128}{2*48}=\frac{-40}{96}
=-5/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+128}{2*48}=\frac{216}{96}
=2+1/4
$